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online_sys/frontend_大健康/clean_duplicate_questions_safe.py
KQL a7242f0c69 Initial commit: 教务系统在线平台
- 包含4个产业方向的前端项目:智能开发、智能制造、大健康、财经商贸
- 已清理node_modules、.yoyo等大文件,项目大小从2.6GB优化至631MB
- 配置完善的.gitignore文件

🤖 Generated with [Claude Code](https://claude.com/claude-code)

Co-Authored-By: Claude Sonnet 4.5 <noreply@anthropic.com>
2025-12-12 18:16:55 +08:00

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#!/usr/bin/env python3
# -*- coding: utf-8 -*-
import re
print("安全清理重复的questions数组...")
# 读取文件
with open('/Users/apple/Documents/cursor/教务系统/frontend_大健康/src/mocks/resumeInterviewMock.js', 'r', encoding='utf-8') as f:
content = f.read()
# 备份
with open('/Users/apple/Documents/cursor/教务系统/frontend_大健康/src/mocks/resumeInterviewMock.js.backup_clean_safe', 'w', encoding='utf-8') as f:
f.write(content)
# 对每个岗位群找到并删除第二个questions数组
industries = ['health_1', 'health_2', 'health_3', 'health_4', 'health_5',
'health_6', 'health_7', 'health_8', 'health_9', 'health_10', 'health_11']
for industry_id in industries:
print(f"处理 {industry_id}...")
# 找到该岗位群
pattern = rf'"id":\s*"{industry_id}"'
match = re.search(pattern, content)
if not match:
continue
start = match.start()
# 找到下一个岗位群或数组结束
next_pattern = rf'"id":\s*"health_\d+"'
next_matches = list(re.finditer(next_pattern, content[start + 10:]))
if next_matches:
end = start + 10 + next_matches[0].start()
else:
# 最后一个岗位群
end_match = re.search(r'\n\];', content[start:])
if end_match:
end = start + end_match.start()
else:
end = len(content)
# 获取该岗位群的内容
industry_content = content[start:end]
# 查找所有questions数组的开始位置
questions_matches = list(re.finditer(r'"questions":\s*\[', industry_content))
if len(questions_matches) > 1:
print(f" 发现 {len(questions_matches)} 个questions数组")
# 找到第二个questions的开始和结束
second_start = questions_matches[1].start()
# 计算括号平衡找到第二个questions的结束
bracket_count = 0
in_array = False
second_end = -1
for i in range(second_start, len(industry_content)):
if industry_content[i] == '[':
if not in_array and '"questions"' in industry_content[max(0, i-20):i]:
in_array = True
bracket_count = 1
elif in_array:
bracket_count += 1
elif industry_content[i] == ']' and in_array:
bracket_count -= 1
if bracket_count == 0:
second_end = i + 1
break
if second_end > 0:
# 找到第二个questions前的逗号
comma_before = industry_content.rfind(',', 0, second_start)
# 删除从逗号到questions结束的内容
if comma_before > 0:
new_industry_content = industry_content[:comma_before] + industry_content[second_end:]
# 替换原内容
content = content[:start] + new_industry_content + content[end:]
print(f" ✓ 删除了 {industry_id} 的第二个questions数组")
# 写回文件
with open('/Users/apple/Documents/cursor/教务系统/frontend_大健康/src/mocks/resumeInterviewMock.js', 'w', encoding='utf-8') as f:
f.write(content)
print("✓ 清理完成!")