a7242f0c69
- 包含4个产业方向的前端项目：智能开发、智能制造、大健康、财经商贸 - 已清理node_modules、.yoyo等大文件，项目大小从2.6GB优化至631MB - 配置完善的.gitignore文件 🤖 Generated with [Claude Code](https://claude.com/claude-code) Co-Authored-By: Claude Sonnet 4.5 <noreply@anthropic.com>
42 lines
1.5 KiB
Python
42 lines
1.5 KiB
Python
#!/usr/bin/env python3
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# -*- coding: utf-8 -*-
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print("查找语法问题...")
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with open('/Users/apple/Documents/cursor/教务系统/frontend_大健康/src/mocks/resumeInterviewMock.js', 'r', encoding='utf-8') as f:
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lines = f.readlines()
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# 跟踪括号栈
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stack = []
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line_num = 0
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for i, line in enumerate(lines, 1):
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for j, char in enumerate(line):
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if char in '{[':
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stack.append((char, i, j))
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elif char in '}]':
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if not stack:
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print(f"第{i}行第{j}列: 多余的关闭符号 '{char}'")
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print(f" 内容: {line.strip()}")
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else:
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opener, open_line, open_col = stack.pop()
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expected = '}' if opener == '{' else ']'
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if char != expected:
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print(f"第{i}行第{j}列: 不匹配的关闭符号")
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print(f" 期望 '{expected}' 但得到 '{char}'")
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print(f" 开始于第{open_line}行第{open_col}列")
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print(f" 内容: {line.strip()}")
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# 检查未关闭的括号
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if stack:
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print("\n未关闭的括号:")
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for char, line_num, col in stack[-5:]: # 显示最后5个未关闭的
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print(f" 第{line_num}行第{col}列: '{char}' 未关闭")
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if line_num <= len(lines):
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print(f" 内容: {lines[line_num-1].strip()}")
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# 检查第6518行附近
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print("\n第6518行附近的内容:")
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for i in range(max(0, 6515), min(len(lines), 6525)):
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if i < len(lines):
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print(f"{i+1}: {lines[i].rstrip()}") |