117 lines
4.8 KiB
Python
117 lines
4.8 KiB
Python
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#!/usr/bin/env python3
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# -*- coding: utf-8 -*-
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import re
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print("清理重复的questions数组...")
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# 读取文件
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with open('/Users/apple/Documents/cursor/教务系统/frontend_大健康/src/mocks/resumeInterviewMock.js', 'r', encoding='utf-8') as f:
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content = f.read()
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# 备份
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with open('/Users/apple/Documents/cursor/教务系统/frontend_大健康/src/mocks/resumeInterviewMock.js.backup_before_cleanup', 'w', encoding='utf-8') as f:
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f.write(content)
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# 对每个岗位群，只保留第一个questions数组（包含正确内容的）
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industries = ['health_1', 'health_2', 'health_3', 'health_4', 'health_5',
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'health_6', 'health_7', 'health_8', 'health_9', 'health_10', 'health_11']
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for industry_id in industries:
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# 找到该岗位群的开始和结束
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pattern = rf'"id":\s*"{industry_id}"'
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match = re.search(pattern, content)
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if match:
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start = match.start()
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# 找到下一个岗位群或数组结束
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next_industry_pattern = rf'"id":\s*"health_\d+"'
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next_matches = list(re.finditer(next_industry_pattern, content[start + 10:]))
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if next_matches:
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end = start + 10 + next_matches[0].start()
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else:
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# 可能是最后一个岗位群
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end_match = re.search(r'\n\];', content[start:])
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if end_match:
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end = start + end_match.start()
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else:
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end = len(content)
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# 获取该岗位群的内容
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industry_content = content[start:end]
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# 查找所有的questions数组
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questions_matches = list(re.finditer(r'"questions":\s*\[', industry_content))
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if len(questions_matches) > 1:
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print(f" {industry_id}: 发现 {len(questions_matches)} 个questions数组")
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# 保留第一个questions（包含正确内容），删除其他的
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# 找到第一个questions的结束位置
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first_q_start = questions_matches[0].start()
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# 找到对应的结束位置（匹配的]）
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bracket_count = 0
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in_questions = False
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first_q_end = -1
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for i in range(first_q_start, len(industry_content)):
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if industry_content[i] == '[':
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if not in_questions and '"questions"' in industry_content[max(0, i-20):i]:
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in_questions = True
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bracket_count = 1
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elif in_questions:
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bracket_count += 1
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elif industry_content[i] == ']' and in_questions:
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bracket_count -= 1
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if bracket_count == 0:
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first_q_end = i + 1
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break
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if first_q_end > 0:
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# 删除第二个questions数组
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if len(questions_matches) > 1:
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second_q_start = questions_matches[1].start()
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# 找到第二个questions的结束位置
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bracket_count = 0
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in_questions = False
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second_q_end = -1
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for i in range(second_q_start, len(industry_content)):
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if industry_content[i] == '[':
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if not in_questions and '"questions"' in industry_content[max(0, i-20):i]:
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in_questions = True
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bracket_count = 1
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elif in_questions:
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bracket_count += 1
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elif industry_content[i] == ']' and in_questions:
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bracket_count -= 1
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if bracket_count == 0:
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second_q_end = i + 1
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break
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if second_q_end > 0:
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# 删除第二个questions（包括前面的逗号）
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# 查找前面的逗号
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comma_pos = industry_content.rfind(',', 0, second_q_start)
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if comma_pos > first_q_end:
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# 删除从逗号到questions结束的内容
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new_industry_content = industry_content[:comma_pos] + industry_content[second_q_end:]
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# 替换原内容
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content = content[:start] + new_industry_content + content[end:]
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print(f" ✓ 已删除 {industry_id} 的重复questions")
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# 清理多余的空行和逗号
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content = re.sub(r',\s*\]', ']', content)
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content = re.sub(r',\s*\}', '}', content)
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content = re.sub(r'\n\s*\n\s*\n', '\n\n', content)
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# 写回文件
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with open('/Users/apple/Documents/cursor/教务系统/frontend_大健康/src/mocks/resumeInterviewMock.js', 'w', encoding='utf-8') as f:
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f.write(content)
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print("✓ 清理完成！")
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